Russian Fighter jet flew at high speed literally quite close to the plane of the U.S. air force in international airspace over the Black sea, according to si-EN-EN Recalling some American bureaucrats.
the incident occurred on may 30, but it was only announced today. The Russian Plane was American at a distance of 10 feet (about three meters).
The fighters flew very close to a scout while, at the same height, then changed course for a while moved for U.S. intelligence, and then left the area in which the aircraft was. Aircraft of the U.S. air force resorted to attempts to evade, reported in the publication, reports RIA " Novosti ". However, on Wednesday, the U.S. Navy destroyer Ross left the Black sea. Last week, the American destroyer became a party to the conflict in the Black sea: the su-24 aircraft of the Russian black sea fleet forced the ship back into international waters in the Eastern part of the Black sea, as the crew of the Ross behaved provocative: the ship went along the edge of the territorial waters of Russia. The American sailors captured the flight of Russian su-24. Remember, Ross together with Ukrainian frigate "Hetman Sahaidachny" held a two-day exercises in neutral waters of the Black sea. According to the press service of the U.S. Navy, " the presence of the destroyer Ross in the Black sea was the enhancement of Maritime security and stability in the region ".